"""
Primfaktorzerlegung
(c) Jürgen Meier
www.3d-meier.de
28.06.2024
"""


n = 11231

p = []

print(n)
i = 2
while i <= n:
    while n % i == 0:
        p.append(i)
        n = n / i
    i = i + 1
print(p)

# Kontrolle
b = 1
for i in range(0, len(p)):
    b = b * p[i]
print(b)